AWS SDK for C++

AWS SDK for C++ Version 1.11.606

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SnapStart.h
1
6#pragma once
7#include <aws/lambda/Lambda_EXPORTS.h>
8#include <aws/lambda/model/SnapStartApplyOn.h>
9#include <utility>
10
11namespace Aws
12{
13namespace Utils
14{
15namespace Json
16{
17 class JsonValue;
18 class JsonView;
19} // namespace Json
20} // namespace Utils
21namespace Lambda
22{
23namespace Model
24{
25
36 {
37 public:
38 AWS_LAMBDA_API SnapStart() = default;
39 AWS_LAMBDA_API SnapStart(Aws::Utils::Json::JsonView jsonValue);
41 AWS_LAMBDA_API Aws::Utils::Json::JsonValue Jsonize() const;
42
43
45
49 inline SnapStartApplyOn GetApplyOn() const { return m_applyOn; }
50 inline bool ApplyOnHasBeenSet() const { return m_applyOnHasBeenSet; }
51 inline void SetApplyOn(SnapStartApplyOn value) { m_applyOnHasBeenSet = true; m_applyOn = value; }
52 inline SnapStart& WithApplyOn(SnapStartApplyOn value) { SetApplyOn(value); return *this;}
54 private:
55
57 bool m_applyOnHasBeenSet = false;
58 };
59
60} // namespace Model
61} // namespace Lambda
62} // namespace Aws
void SetApplyOn(SnapStartApplyOn value)
Definition SnapStart.h:51
SnapStart & WithApplyOn(SnapStartApplyOn value)
Definition SnapStart.h:52
AWS_LAMBDA_API SnapStart(Aws::Utils::Json::JsonView jsonValue)
AWS_LAMBDA_API Aws::Utils::Json::JsonValue Jsonize() const
AWS_LAMBDA_API SnapStart()=default
AWS_LAMBDA_API SnapStart & operator=(Aws::Utils::Json::JsonView jsonValue)
SnapStartApplyOn GetApplyOn() const
Definition SnapStart.h:49
Aws::Utils::Json::JsonValue JsonValue